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A better understanding of zrmesher

I am trying to understand how z-remesher works.

I had sphere with 45 million polygons. Just the default sphere of whose polycount I increased with divide button.

Then I used z-remesher to reduce polycount and this was the result.

What exactly is the number 5 in the target polygon count?

It took good 5-6 minutes for the whole operation to complete. I have acer nitro laptop with 8th gen i7 processor, 16GB RAM and 4GB of Nvidia GTX1050 Ti graphics.

Is there a way to reduce polycount with some measurable figure?

For example, if I have polycount of 9.8 million and I want to bring it down to 5.6 million?

Have you tried ZPlugin, Decimation Master?

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Just tried decimation master. The same sphere with minimal pulls made using standard brush.

13 minutes have passed and still pre-processing.

Edit…

Processing took 20 minutes. Decimation happened in 30 seconds. But I don’t understand the calculation. It was by default set to 20% decimation and I got 18.048 polygons.

(A/The) purpose of ZRemesher is to automatically retopologize your model to a much lower polycount using predominantly quad polygons. This allows it to be subdivided to higher levels to preserve detail but lowered to a smaller subdivision level for larger scale operations like movement, smoothing and major form changes.

The number 5 in the polycount refers to 5k (5000) polygons. Max on the slider is 100k. You can target up to 250k through the Gizmo:Remesh by ZRemesher option.

As for say going from 9.6M to 5.8M, not with a ZRemesher control directly. More likely to ZRemesh to a lower level and then subdivide up to the target 5.8M, knowing that each subdivision multiplies polycount by near enough to 4. So ZRemeshing 9.6M to about 5.6k will give 6 subdivision to reach about 5.8M.

You could Decimate as suggested to give somewhat more control over polycounts but the mesh will be comprised only of triangles which has it’s own uses and limitations. I replicated your trial, without the move deformation, and got 8.914 at 20%. That is 8.914 million points which is pretty close to 20% of my starting 44.57M points. Your result will vary because of the deformation. Remeshing with Decimation Master or ZRemesher will adjust mesh size and density to preserve detail. Also note that Decimation Master shows estimated counts of both polys and points when adjusting the % decimation slider. Looks like the percentage refers to points. Point count and polycount are almost identical when polys are quads but polycount is about twice point count when polys are triangles. You can adjust the %, poly or point counts. So if you want a specific polycount then adjust that value rather than the % decimation slider.

Check out Intro to Zbrush by Michael Pavlovich. ZRemesher is #45.

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Thanks. I’ll play with the point settings for counts and polycounts. Also I’ll go through the video you shared.

Hello @archz2 ,

The target polycount in ZRemesher is more of a suggestion to ZRemesher. It will still prioritize other settings if it needs to in order to preserve form. This is particularly true if the Adaptive Density functions are enabled.

This is explained in the ZRemesher documentation:

http://docs.pixologic.com/reference-guide/tool/polymesh/geometry/zremesher/

ZRemesher is useful for simplifying a mesh with clean, decent quality topology. If you want more absolute control over the polycount and don’t care about the quality of the topology, Decimation Master might be a better fit.

:slightly_smiling_face:

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How do I know what exactly is z-remesher prioritizing?

adaptive size
curve strength
or polygon count?

What are units in adaptive size and curve strength? There are no units specified there. Is it percentage or something else?

And the maximum limit of zremesher is 100k polygons. What if I want to do z-remeshing to 2 million?